[dm-crypt] recover old crypt partition
arno at wagner.name
Thu Jan 6 20:31:35 CET 2011
On Thu, Jan 06, 2011 at 04:33:52PM +0100, Jan Christoph Uhde wrote:
> > "sign"? Do you mean "character"? If so, 13 known, 6 unknown and
> > another 4 from 5 possibilities gives you 256^6 * 5^4 = 1.76*10^17
> > possibilities, which is a bit outside of what you can just try.
> > Anything more known about the uunknowen ones?
> the password is in the From:
> UKKKKKKKKKKKKKUUU where U in %,#,$,_,!,^
Ah. And KK...KK is known? What are the other unknowns besides
the Us? The Us give you 6^4 possibilities, which is about
> > Is this plain dm-crypt?
> i used cryptsetup in debian sid
Yes, but did you create a LUKS partition or a plain dm-crypt one?
The default would have been dm-crypt. Hmm. That would mean the cipher
is probably the old default of aes-cbc-plain. Can anybody confirm that
for Debian SID?
> PS: I did not receive a mail jet so please excuse that i am not replying
> i a proper way.
You will not get one. This list is actually also for discussing
these questions. If you want to have a private discussion, you
can reach me at arno at wagner.name
Arno Wagner, Dr. sc. techn., Dipl. Inform., CISSP -- Email: arno at wagner.name
GnuPG: ID: 1E25338F FP: 0C30 5782 9D93 F785 E79C 0296 797F 6B50 1E25 338F
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